From 7ce6ff9e5de99e7b72019c7de82fb438fe1dc5a0 Mon Sep 17 00:00:00 2001 From: Michel Lespinasse Date: Mon, 8 Oct 2012 16:31:01 -0700 Subject: rbtree: coding style adjustments Set comment and indentation style to be consistent with linux coding style and the rest of the file, as suggested by Peter Zijlstra Signed-off-by: Michel Lespinasse Cc: Andrea Arcangeli Acked-by: David Woodhouse Cc: Rik van Riel Cc: Peter Zijlstra Cc: Daniel Santos Cc: Jens Axboe Cc: "Eric W. Biederman" Signed-off-by: Andrew Morton Signed-off-by: Linus Torvalds --- lib/rbtree.c | 42 +++++++++++++++++++++++------------------- 1 file changed, 23 insertions(+), 19 deletions(-) (limited to 'lib') diff --git a/lib/rbtree.c b/lib/rbtree.c index a38e473d8fe7..08926709b4f9 100644 --- a/lib/rbtree.c +++ b/lib/rbtree.c @@ -363,8 +363,7 @@ void rb_erase(struct rb_node *node, struct rb_root *root) child = node->rb_right; else if (!node->rb_right) child = node->rb_left; - else - { + else { struct rb_node *old = node, *left; node = node->rb_right; @@ -406,17 +405,15 @@ void rb_erase(struct rb_node *node, struct rb_root *root) if (child) rb_set_parent(child, parent); - if (parent) - { + if (parent) { if (parent->rb_left == node) parent->rb_left = child; else parent->rb_right = child; - } - else + } else root->rb_node = child; - color: +color: if (color == RB_BLACK) __rb_erase_color(child, parent, root); } @@ -529,8 +526,10 @@ struct rb_node *rb_next(const struct rb_node *node) if (RB_EMPTY_NODE(node)) return NULL; - /* If we have a right-hand child, go down and then left as far - as we can. */ + /* + * If we have a right-hand child, go down and then left as far + * as we can. + */ if (node->rb_right) { node = node->rb_right; while (node->rb_left) @@ -538,12 +537,13 @@ struct rb_node *rb_next(const struct rb_node *node) return (struct rb_node *)node; } - /* No right-hand children. Everything down and left is - smaller than us, so any 'next' node must be in the general - direction of our parent. Go up the tree; any time the - ancestor is a right-hand child of its parent, keep going - up. First time it's a left-hand child of its parent, said - parent is our 'next' node. */ + /* + * No right-hand children. Everything down and left is smaller than us, + * so any 'next' node must be in the general direction of our parent. + * Go up the tree; any time the ancestor is a right-hand child of its + * parent, keep going up. First time it's a left-hand child of its + * parent, said parent is our 'next' node. + */ while ((parent = rb_parent(node)) && node == parent->rb_right) node = parent; @@ -558,8 +558,10 @@ struct rb_node *rb_prev(const struct rb_node *node) if (RB_EMPTY_NODE(node)) return NULL; - /* If we have a left-hand child, go down and then right as far - as we can. */ + /* + * If we have a left-hand child, go down and then right as far + * as we can. + */ if (node->rb_left) { node = node->rb_left; while (node->rb_right) @@ -567,8 +569,10 @@ struct rb_node *rb_prev(const struct rb_node *node) return (struct rb_node *)node; } - /* No left-hand children. Go up till we find an ancestor which - is a right-hand child of its parent */ + /* + * No left-hand children. Go up till we find an ancestor which + * is a right-hand child of its parent. + */ while ((parent = rb_parent(node)) && node == parent->rb_left) node = parent; -- cgit v1.2.3-58-ga151